There are no three consecutive whole numbers which multiply to 81.
3x4x5=60
4x5x6=120
The nearest we can get to 81 by using 'consecutive' decimal numbers to 4 places of decimals is to use the sequence:
However, most people would argue that the expression 'consecutive numbers' means 'consecutive whole numbers.'
If this is so, then 'numbers' such as 3.4038 are disallowed.
But if the question should be "Which number multiplied by itself three time comes to 81? then an answer could worked out in this way ....
Use the number 3.
Multiply 3 by itself, but do this once. The answer is 9 (i.e. 3x3)
Then multiply the answer again by 3. This will be the second time you have performed the multiplication. The answer is 27 (9x3).
Then multiply by 3 a third time, and the answer will be 81 (27x3)
Even so, the usual way to calculate three multiplied by itself 3 times is to set it out like this: 3x3x3. But this gives the answer 27, which is not what we are looking for in the question!
3 & 27
162
They are: 2 times 81 = 162
Factors are numbers you can multiply together to get another number. 81: 1, 3, 9, 27, 81
Let the second number be x, then the three consecutive numbers are x-1, x, x+1, and their sum is: (x-1) + x + (x+1) = 81 3x = 81 x = 27 So the three numbers are 27-1, 27, 27+1 = 26, 27, 28
9 x 9 = 81 :(
3 & 27
Just use the definition of geometric mean. Multiply the two numbers, then take the square root of the result. (To take the geometric mean of three numbers, multiply all of them, then take the cubic root, etc.)
162
They are: 2 times 81 = 162
Factors are numbers you can multiply together to get another number. 81: 1, 3, 9, 27, 81
These: 1 x 81, 3 x 27, 9 x 9
1 x 81, 3 x 27, 9 x 9.
-9 and -9 multiply to get 81. ■
245
There are no two real numbers that will add to -9 and multiply to 81. Using complex numbers, the two numbers are: (-9/2 + i9/2√3) and (-9/2 - i9/2√3)
The numbers that add to get 6 and multiply to get 81 are 3 and 3.