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If three consecutive numbers add up to eighteen what is the smallest of the numbers?
Gloriajanke
Let be x the smallest number. So, the second number will be x + 1, and the third one will be x + 2. So,
x + (x + 1) + (x + 2) = 18
3x + 3 = 18 subtract 3 to both sides;
3x = 15 divide by 3 to both sides;
x = 5
Thus, the smallest number is 5. - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Couldn't you also just use the factors of 18: 1, 2, 3, 6, 9, 18 Prime Numbers: 3 x 3 x 2 Smallest Number is then 2.
You are right, 2 is the smallest Prime number in the prime factorization of 18. But, the question is that three consecutive numbers are added up to 18, and 3 x 3 x 2 is a multiplication. However, 2 and 3 are consecutive so the third number will be 4 not 3. I didn't catch the consecutive part. Good call and thanks for the input.
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∙ 15y ago
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