the answer is a
2a. (a, b and c are all equal.)
Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.
to solve ab=c+a for a:Divide both sides by b, so:a= (c+a)/b
A.
the answer is a
A+c= 2a+b
a=24 b=16 c=18
z remains undefined.
2a. (a, b and c are all equal.)
Because there is no way to define the divisors, the equations cannot be evaluated.
The letter c is a variable. Since c appears in all three c+c+c=6, C has to equal the same number each time. So c equals 2!!!!
2s-2b= a+b+c-2b simplified that would be a+c-b.
73474949444999272725678251628909813.345267777777776663
Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.
to solve ab=c+a for a:Divide both sides by b, so:a= (c+a)/b
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."