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Earn +20 ptsQ: If x equals 2 and y equals 5 then 7x equals 4y equals?
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How do you solve 7x plus 4y equals 39 2x plus 4y equals 14 into an order pair?
7x+4y = 39 2x+4y = 14 Subtract the equations in order to eliminate y: 5x = 25 Divide both sides by 5 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 1
If x equals 3 and y equals 2 then 7x plus 5y equals?
7x + 5y 7(3) + 5(2) 21 + 10 = 31
9x equals 53 - 4y 3y equals 26 - 4x?
(5, 2)
What are the points of intersection when the line x -y equals 2 crosses the curve x squared - 4y squared equals 5?
If: x -y = 2 then x^2 = y^2 +4y +4 If: x^2 -4y^2 = 5 then x^2 = 4y^2 +5 So: 4y^2 +5 = y^2 +4y +4 Transposing terms: 3y^2 -4y +1 = 0 Factorizing the above: (3y -1)(y -1) = 0 meaning y = 1/3 or y = 1 Substitution into the original linear equation intersections are at: (7/3, 1/3) and (3, 1)
What is the value of x that satisfies the equation 2 log 4 Bracket 7 x Bracket - 5 equals 0 Is - Please show working out?
2log4(7x) - 5 = 0 2log4(7x) = 5 log4(7x) = 5/2 7x = 45/2 =(41/2)5 = 25 = 32 x = 32/7
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