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If x=2, then 7x = 14 and if y=5 then 4y=20.

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Q: If x equals 2 and y equals 5 then 7x equals 4y equals?
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What is the slope and y-intercept of 4y - 5 equals 7x?

4y - 5 = 7x ∴y = 7/4x + 5/4 slope = 7/4, or 1.75 4y - 5 = 7x ∴4y/7 - 5/7 = x ∴4y/7 - 5/7 = 0 ∴4y = 5 ∴y = 1.2 the y-intercept is 1.2


How do you solve 7x plus 4y equals 39 2x plus 4y equals 14 into an order pair?

7x+4y = 39 2x+4y = 14 Subtract the equations in order to eliminate y: 5x = 25 Divide both sides by 5 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 1


What is the answer to -7x plus 5 equals -9?

-7x + 5 = -9 -7x = -14 7x = 14 x = 2


What is the ordered pair of 4x-4y12 and -7x 4y-36?

If you mean: 4x -4y = 12 and -7x +4y = -36 then x = 8 and y = 5


How do you write 8x plus 4y equals 5?

8x plus 4y equals 5 is 8x + 4y = 5.


What is the slope of 7x plus 5 for x equals 2?

7x is still the slope, no matter what x equals.


23 equals 7x plus 7x-5?

23 = 7x + 7x - 5 = 14x - 5 14x = 23 + 5 = 28 x = 28/14 = 2


If x equals 3 and y equals 2 then 7x plus 5y equals?

7x + 5y 7(3) + 5(2) 21 + 10 = 31


What are the points of intersection of the line x -2 equals 2 with x2 -4y2 equals 5?

x - 2 = 2 → x = 4 → x² - 4y² = 5 → 4² - 4y² = 5 → 4y² = 16 - 5 → 4y² = 11 → y² = 11/4 → y = ± √(11/4) → The points of intersection of x - 2 = 2 with x² - 4y² = 5 are (4, -√(11/4)) ≈ 4, -1.658) and (4, √(11/4)) ≈ 4, 1.658)


9x equals 53 - 4y 3y equals 26 - 4x?

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6x plus 4y equals 32 -6x plus 4y equals 8?

6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2


Is x equals 1 a solutin of equation 7x-2 equals 5?

yes.