3
1/36
Assuming that a dice roll is purely random, there is a 1 in 6 probability of landing on any number. Since the second roll depends on the probability of the first, they factor together: First Roll: 1/6 Second Roll: (1/6)(1/6) = 1/36 If you were rolling both dice at once, however, the math would be completely different.
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.
It is 6/36 = 1/6.
For a single roll of a pair of fair dice, the answer is 1/36.
2, always with 2
Assuming normal dice, the answer is 0, since it is impossible to roll a 1 on 2 dice = the least you can get is 1 + 1 = 2.
The odds are 1 in 36 that you will roll a sum of 2 in a single roll of two fair dice.
1/2
1 in 6. Basically dice 1 can roll any number So the odds are that dice 2 has the same number as dice 1, or 1 in 6
No you can decide if you want to roll one or 2 of the dice.
You cannot roll "a dice" because it is one die, many dice. If you roll an ordinary, 6 faced die, the probability that it will land on 1 is 1/6.
1/36
4/36 or 1/9
It is 2/6 = 1/3
there is six sides on a dice and three of them is odd3/6=1/2=50%it's a 50% chance to roll an odd number