1 in 6.
Basically dice 1 can roll any number
So the odds are that dice 2 has the same number as dice 1, or 1 in 6
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The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)
The odds of rolling snake eyes (two ones) on a pair of dice is 1 in 36, since there are 36 possible outcomes when rolling two dice. To find the odds of rolling snake eyes twice in a row, you multiply the probabilities: ( \frac{1}{36} \times \frac{1}{36} = \frac{1}{1296} ). Therefore, the odds of rolling snake eyes twice in a row are 1 in 1296.
There is a one out of four chance of having both dice even numbers.
The probability is 1/36.
The odds are 1 in 36 that you will roll a sum of 2 in a single roll of two fair dice.