Wiki User
∙ 12y ago2 in 6, or 1 in 3, or about 0.3333.
Wiki User
∙ 12y agoI'm assuming you're looking for the probability that you roll either a one or six at least once. So the problem can be rewritten as: 1 - probability of rolling 60 times and never getting ones or sixes = 1 - (2/3)^60
The probability is 100% since a single die has numbers 1-6, all of which are greater than zero (assuming that the die is a fair standard die and the results of the roll may be analyzed regardless of where the die ended up).
When you roll a 6 sided die there are 6 possible outcomes. 1,2,3,4,5,6. Out of these 3 are multiples of 2. Therefore the Probability of getting a multiple of 2 is (3/6) which simplifies to (1/2) or a half.
I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
1:6
On a single roll of a normal die the probability of getting a 7 is 0.
1/6
If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.
On a single roll it is 2/3.
On a single roll of a fair, six-sided die, it is 1/2.
For a 6 sided die, each number 1 - 6 has equal probability. So, probability of rolling a 5 is 1/6.
5/12
The probability of rolling a sum of 12 in a single roll of two dice is 1 in 36, or about 0.0278.
Two thirds (2/3)
On a single roll of a fair die, the probability is 1/3.
5/36 in a single roll.