I have to assume that you include 5 in your question then there are 6 sides and you can only win on 3 (1/3/5 ) or 3/6 which is 50% probability.
If the dice or die are 6 sided, then you would most likely roll a 6 13.33333 times, which rounds to 13.
He should expect it 100 times.
40 times
The expected number of times is the probability x number of throws. Since you have a prob of 1/6 for a seven, then (1/6) * 160 = 26.67 times you would have success. We generally would round up the expected number of successes to the whole number 27.
about 18...hope this helps(:
If the dice or die are 6 sided, then you would most likely roll a 6 13.33333 times, which rounds to 13.
You can expect the spinner to land an odd number 25 times out of 50.
1/6 of 84
He should expect it 100 times.
A fair cube 60 times.
I would expect it to land on a number of 4 or higher 50% of the time or roughly 24 times.
homework is hard
33
Type your answer here... 15
well by 19 tmes
If it is a fair die, the probability of throwing a 4 in a single go is 1/6. That is, you expect to get a 4 in 1/6 of the throws. So for 84 throws you would expect to get a 4 in 84*(1/6) = 14 times.
The expected value is 20 times.