P(4) = 1/6 x 84 = 14 times.
If it is a fair die, the probability of throwing a 4 in a single go is 1/6. That is, you expect to get a 4 in 1/6 of the throws. So for 84 throws you would expect to get a 4 in 84*(1/6) = 14 times.
You can expect the spinner to land an odd number 25 times out of 50.
I would expect it to land on a number of 4 or higher 50% of the time or roughly 24 times.
A fair coin would be expected to land on heads 10 times on average.
the answer is the probability 6o =1/6 = 60%
homework is hard
If the dice or die are 6 sided, then you would most likely roll a 6 13.33333 times, which rounds to 13.
If it is a fair die, the probability of throwing a 4 in a single go is 1/6. That is, you expect to get a 4 in 1/6 of the throws. So for 84 throws you would expect to get a 4 in 84*(1/6) = 14 times.
You can expect to get a 5 about 15 times out of 90.
75
60
He should expect it 100 times.
You would expect it 0.3 of the times.
You can expect the spinner to land an odd number 25 times out of 50.
When rolling a regular 6-faced die, the probability of rolling a 5 on any single roll is ( \frac{1}{6} ). If you roll the die 1200 times, you would expect to get a 5 approximately ( 1200 \times \frac{1}{6} = 200 ) times. Therefore, you would expect to roll a 5 about 200 times.
I would expect it to land on a number of 4 or higher 50% of the time or roughly 24 times.
I have to assume that you include 5 in your question then there are 6 sides and you can only win on 3 (1/3/5 ) or 3/6 which is 50% probability.