In the equation m = k + 3, m is the:
k=275 First find the prime factorization of 2750 and 360: 2750=2*53*11 360=23*3*5 Now you want the smallest positive integers, k and m, such that: 23*3*5*k=2*53*11*m In order for the two sides of the equation to be equal, the right-hand side of the equation must contain the prime factors on the left-hand side to the same power as the prime factors on the left-hand side. The smallest integer value of m for which this is true is: m=22*3 Now solve for k: 23*3*5*k=2*53*11*22*3 k=(2*53*11*22*3)/(23*3*5)=52*11=275
(k*m)3 = k3*m3
m-15=3 m-15+15=3+15 m=3+15 m=18
2
Assuming that you meant that the equation is y=3x+1, the slope is 3. This is because the equation of any line in the form of y=mx+b has a slope of "m". Therefore, the value of m in this equation is 3.
The rate of the reaction is calculated using the rate equation: rate = k[A]^3[B]^2. Given k = 0.01, [A] = 2 M, and [B] = 3 M, the rate can be determined by substituting these values into the rate equation and solving for the rate.
The equation given is not enough to solve for k, m, and n as it has 3 unknowns and only 1 equation. You need at least 2 or more equations to solve for the unknowns.
The rate of the reaction can be calculated using the rate law equation rate = k[A]^m[B]^n. Plugging in the given values k = 0.2, m = 1, n = 2, [A] = 3 M, and [B] = 3 M into the equation gives rate = 0.2 * (3)^1 * (3)^2 = 16.2 M/s.
To find the rate constant ( k ) of the reaction, we can use the rate law equation: [ \text{rate} = k [A]^m [B]^n ] Given that the rate is 0.2 mol L⁻¹ s⁻¹, with concentrations ( [A] = 3 , \text{M} ), ( m = 1 ), ( [B] = 3 , \text{M} ), and ( n = 2 ), we can substitute these values into the equation: [ 0.2 = k (3)^1 (3)^2 ] This simplifies to: [ 0.2 = k (3)(9) = 27k ] Solving for ( k ), we find: [ k = \frac{0.2}{27} \approx 0.00741 , \text{L}^2 \text{mol}^{-2} \text{s}^{-1} ]
K is two times m add 1 k = (2 m ) + 1 k=2m+1
The equation for the period of harmonic motion is T = 2π√(m/k), where T is the period, m is the mass of the object, and k is the spring constant.
k=275 First find the prime factorization of 2750 and 360: 2750=2*53*11 360=23*3*5 Now you want the smallest positive integers, k and m, such that: 23*3*5*k=2*53*11*m In order for the two sides of the equation to be equal, the right-hand side of the equation must contain the prime factors on the left-hand side to the same power as the prime factors on the left-hand side. The smallest integer value of m for which this is true is: m=22*3 Now solve for k: 23*3*5*k=2*53*11*22*3 k=(2*53*11*22*3)/(23*3*5)=52*11=275
i dont know but still you are not answering me.why?
Rate = k[A]m[B]n
(k*m)3 = k3*m3
No, it is not m. The answer is 9, which has the equation 6+3.
The equation for a vertical spring-mass system is given by: m a -k x where: m mass of the object a acceleration of the object k spring constant x displacement from the equilibrium position