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This integral cannot be performed analytically. Ony when the integral is taken from 0 to infinity can it be computed by squaring the integral and applying a change of variable (switching to polar coordinates).

if desired I could show how to do this.

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12y ago
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Q: Integrate e raised to power x raised to power 2?
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What is e raised to the 0th power?

e raised to the 0 power is 1


How do you integrate x power x?

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int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================


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e 2x = (1/2) e 2x + C ============


What is the anti derivative of e raised to 6?

Well the number e, raised to 6 (e^6) is just a number (a constant), so you integrate a constant times dx gives you that constant times x + C --> x*e^6 + C


How do you integrate e power minus 2x?

∫e^(-2x) dx Let u = 2x du= 2 dx dx=(1/2) du ∫e^(-2x) dx = (1/2) ∫e^-u du = (1/2) (-e^-u) = -e^-u /2 + C = -e^-(2x) / 2 + C


What is the first derivative of e raised to the power of x?

The first derivative of e to the x power is e to the power of x.


How to integrate of e to the power of -2x with x to the power of 2?

e-2x^2 cannot be integrated, only approximated unless there is an additional x attached to the front of the e, otherwise this function is not integrable Actually, it can be integrated, but it requires multivariable calculus and a conversion from cartesian to polar form to do so.


E raised to the power of x equal 10?

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How do you integrate e-2x?

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