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32 32 4 +4 = 8 8 + 6 = 14 14 + 8 = 22 22 + 10 = 32 The sequence starts at 4 and then adds 4, to get 8, then adds 6 to get 14, then adds 8, to get 22, so by extension the next number is 22 + 10. The number being added to the previous number in the sequence starts at 4 and rises by 2 each time.
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
10. Then 12, 14, 16, 18, 20, 22, 24, etc.
In this case, 22 would have the value of 11.
An arithmetic sequence in one in which consecutive terms differ by a fixed amount,or equivalently, the next term can found by adding a fixed amount to the previous term. Example of an arithmetic sequence: 2 7 12 17 22 ... Here the the fixed amount is 5. I suppose any other type of sequence could be called non arithmetic, but I have not heard that expression before. Another useful kind of sequence is called geometric which is analogous to arithmetic, but multiplication is used instead of addition, i.e. to get the next term, multiply the previous term by some fixed amount. Example: 2 6 18 54 162 ... Here the muliplier is 3.