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our teacher said"0 is not a multiple of 9"
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Multiples of 0?
Every multiple of 0 is 0. Examples 0 x 0 = 0 0 x 9 = 0 0 x 43232434 = 0
What is the smallest number after 8000 divisible by 9?
That is 8001. For a number is divisible by 9, the digits must sum up to 9 (or a multiple of 9). So for 8000, the digits sum to 8 [8 + 0 + 0 + 0 = 8]. So you're only 1 away from 9 [8 + 0 + 0 + 1 = 9]
How do you know if a number is a multiple of 9?
If you add up all the digits in a number and the sum is a multiple of 9 then the original number is also a multiple of 9. For example; 12,167,314,839,0181+2+1+6+7+3+1+4+8+3+9+0+1+8 = 54 = 6 x 9 therefore the original number is a multiple of 9, actually 1,351,923,871,002 x 9Use a calculator and try to divide the number by 9. If 9 divides into the number a whole number of times then the number is a multiple of 9.
Is 33 a multiple of 9?
No, 33 is not a multiple of 9.
What is the common multiple of 1 and 9?
Any multiple of 9.
Does 9 have a multiple that ends in 0?
90
Why didn't the first five multiples of 9 start with 0?
0 isn't the first multiple of 9.
What is the least multiple of 9?
0 x 9 = 0or 1 x 9 = 9
How is 0 the first 10 multiples of 9?
0 = 01 = 92 = 183 = 274 = 365 = 456 = 547 = 638 = 729 = 81
How do you calculate multiples of 9?
If the digits of a number add up to 9 or a multiple of nine, it is a multiple of nine. For example, 108. 1+0+8=9, so 108 is a multiple of 9. Also, 9981. 9+9+8+1=27. 27 is a multiple of 9, so 27 is also a multiple of 9.Enjoy
Multiples of 0?
Every multiple of 0 is 0. Examples 0 x 0 = 0 0 x 9 = 0 0 x 43232434 = 0
Is 270 a multiple of 3?
2+7+0=9 and 9 is divisible by 3. Therefore 270 is a multiple of 3.This works for 3,9 and 27.
What is the lowest common multiple for 2 3 and 9?
We see that we must find a number n such that it satisfies the condition: n ≡ 0 (mod 2) ≡ 0 (mod 3) ≡ 0 (mod 9) Since 9 is a multiple of 3, we can forget about the 0 (mod 3). Since 2 and 9 are relatively prime, the Chinese Remainder Theorem states that there indeed exists a number n such that it satisfies n ≡ 0 (mod 2) ≡ 0 (mod 9). Now let 2K represent some multiple of 2, and set it congruent to 0 (mod 9): 2K ≡ 0 (mod 9) This is a particularly easy case; 2K would have to equal some multiple of 9 for it to satisfy this expression. Therefore, K = 9 and n must = 18c, where c is an arbitrary multiplier. This is your new modulus: n ≡ 0 (mod 18) Any n that satisfies this condition will also satisfy n ≡ 0 (mod 2) ≡ 0 (mod 3) ≡ 0 (mod 9).
What is a multiple of 9 between o and 100?
They are: 18 27 36 45 54 63 72 81 90 and 99
What is the smallest number after 8000 divisible by 9?
That is 8001. For a number is divisible by 9, the digits must sum up to 9 (or a multiple of 9). So for 8000, the digits sum to 8 [8 + 0 + 0 + 0 = 8]. So you're only 1 away from 9 [8 + 0 + 0 + 1 = 9]
What multiple of 70 between 0 and 630 has 9 as one of its digits?
The number is 490.
Is 0 a multiple of any number?
It depends for example: 0, 3, 6 This times table starts with 0. 3, 6, 9 This one does to it is just not included in the times table. So yes 0 is a multiple of all numbers.
