To determine if 475 is divisible by 2, we check if it is an even number - it is not, so it is not divisible by 2. To check for divisibility by 3, we add the digits (4+7+5 = 16) and see if the sum is divisible by 3 - it is not, so 475 is not divisible by 3. For 5, we check if the last digit is 0 or 5 - it is not, so it is not divisible by 5. For 4, we look at the last two digits (75) and check if they form a number divisible by 4 - they do not, so 475 is not divisible by 4. Lastly, for 10, we check if it ends in 0 - it does not, so 475 is not divisible by 10.
Out of that list, 40 is divisible by 2, 4, 5, 8 and 10.
7 + 4 + 1 = 12 which is divisible by 3, so 741 is divisible by 3 741 is odd, all multiples of 4 are even, 741 is not divisible by 4 (Alternatively 4 x 2 + 1 x 1 = 9 which is not divisible by 4, so 741 not divisible by 4) All multiples of 5 end with 5 or 0, 741 ends with 1, so 741 not divisible by 5 To be divisible by 6, the number must be divisible by 2 (even) and divisible by 3.741 is odd, so not divisible by 2, so 741 is not divisible by 6 7 + 4 + 1 = 12 which is not divisible by 9, so 741 is not divisible by 9 All multiples of 10 end with 0, 741 ends with 1 so 741 is not divisible by 10 Summary: 741 is divisible by 3, but not by 4, 5, 6, 9 nor 10.
135
The least number divisible by 2, 3, 4, 5, 6, 9, and 10 is 180.
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
3, 5, 9, yes. 2, 10, no.
No it is divisible by 5 at least 675/5 = 135 so also divisible by 135, and so on ...
810/2 = 405 810/3 = 270 * 810/4 = 202.5 810/5 = 162 810/6 = 135 810/9 = 90 810/10 = 81 so 810 is divisible by 2 3 5 6 9 10 but not by 4
135
From that list, 20 is divisible by 2, 4, 5 and 10.
135. Every increase of 30 is also. Such as 165, 195, 225.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
650130 is not divisible by 4, but it is divisible by 2, 3, 5, 6, and 10
135 135 / 3 = 45 135 / 5 = 27
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
To determine if 621 is divisible by 2, we look at the last digit which is 1, and since it is odd, 621 is not divisible by 2. To check divisibility by 3, we sum the digits: 6 + 2 + 1 = 9, which is divisible by 3, so 621 is divisible by 3. For divisibility by 4, we examine the last two digits, which are 21, and since 21 is not divisible by 4, 621 is not divisible by 4. Since the last digit is not 0 or 5, 621 is not divisible by 5. 621 is not divisible by 6 as it is not divisible by both 2 and 3 simultaneously. Lastly, since 621 ends in 1, it is not divisible by 10.