There are 40 odd numbers between 20 and 100. Remember that an odd number is every second number. There are 80 numbers between 20 and 100, so there are 40 odd numbers and 40 even numbers.
An even multiple of 20 is equal to 20 multiplied by an even number, that is 20 multiplied by 2k where k is any integer.
When there is an even number of items in the data set the median is the mean average of the middle two. The middle two are the two items themselves, namely 20 and 40, so the median is (20 + 40)/2 = 30.
I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40
45
There are 40 odd numbers between 20 and 100. Remember that an odd number is every second number. There are 80 numbers between 20 and 100, so there are 40 odd numbers and 40 even numbers.
No, 40 is an even number.
40 is an even number - it is divisible by 2 to produce a whole number
There are 20 odd numbers in 40.
Even numbers are numbers which are multiples of 2 (they can be divided by 2). 40\2 = 20 This means that 40 is an even number.
No.
An even multiple of 20 is equal to 20 multiplied by an even number, that is 20 multiplied by 2k where k is any integer.
There can be no number with an odd sum of 8 because 8 is not odd!
Even because it is divisible by 2.
21 23 25 27 29 31 33 35 37 39
If you add an even number with another even number, you will always get the sum as an even number. Ex: 22 + 44 = 66
That number is 36.