1, 3, 83, 249.
Yes, the result is 83.
It is divisible by 10, but not by 3.
An integer that is divisible by 100 with a remainder. The answer should be a whole number as well.eg. 3/100 = 0.03therefore 3 is not evenly divisible by 100300/100 = 3therefore 300 is evenly divisible by 100
855 and 875 are both evenly divisible by 5. 855 is evenly divisible by 3, but 875 isn't.
1, 3, 83, 249.
2+4+9=15 which is divisible by 3 so 249 is divisible by 3, thus 249 is not a prime number
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
693 is evenly divisible by 3. You can tell that at a glance because every one of its digits is evenly divisible by 3.
939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3
It is not evenly divisible.
Yes - 747/3 = 249
Yes, the result is 83.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.
434 is evenly divisible by 2.It is not evenly divisible by 3, 6, or 9.
It is divisible by 10, but not by 3.
It is not evenly divisible by 3. 10867/3 = 3622.333333333