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What is the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers?
Oh, dude, the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers is 3. Why? Because any set of consecutive odd numbers will include multiples of 3, ensuring that the sum will be divisible by 3. So, like, 3 is the magic number here.
Is the sum of an even whole number and an odd whole number always odd?
Yes --------------------------------------------- Let n be an integer. Then 2n is an even number Let m be an integer. Then 2m is an even number and 2m + 1 is an odd number. Then: even + odd = (2n) + (2m + 1) = (2n + 2m) + 1 = 2(n + m) + 1 = 2k + 1 (where k = m + n) which is an odd number.
Twice what number is equal to three times that number?
let the number be n. Then: 2n = 3n ⇒ 2n - 2n = 3n - 2n ⇒ 0 = n ie, the number is zero.
What is the formula for finding the nth hexagonal number?
The nth hexagonal number is given by the formula: hn = 2n * (2n - 1) / 2
How many of the whole numbers less than 100 are 10 greater than an odd whole number?
To find the number of whole numbers less than 100 that are 10 greater than an odd whole number, we can set up an equation. Let x represent the odd whole number. Therefore, the number that is 10 greater than x is x + 10. Since x is odd, it can be represented as 2n + 1, where n is a non-negative integer. Substituting this into the equation x + 10 = 2n + 1 + 10, we get 2n + 11. To find the number of such numbers less than 100, we need to find the largest possible value of n such that 2n + 11 < 100. Solving for n, we get n < 44.5, which means the largest possible integer value for n is 44. Therefore, there are 45 odd whole numbers less than 100 that are 10 greater than an odd whole number.
