Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth triangular number is 0.5*n*(n+1)
The Nth term formula for oblong numbers is N = N(N+1)
Fn = Fn-1 + Fn-2 And F0 = F1 = 1
Oh, dude, finding the nth term is like finding a needle in a haystack, but with numbers. So, if you look closely at this pattern, you'll notice that the difference between consecutive terms is increasing by 2 each time. It's like a math puzzle, but with less fun and more numbers. So, the nth term can be calculated by the formula n^2 + 4.
it is 6n
No, it will be a formula, because "the nth term" means that you have not defined exactly which term it is. So, you make a formula which works for ANY term in the sequence.
V = n3
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth formula is Un = 1422303846 for all n.
The nth triangular number is 0.5*n*(n+1)
a + (n-1)d = last number where a is the first number d is the common difference.
The Nth term formula for oblong numbers is N = N(N+1)
Fn = Fn-1 + Fn-2 And F0 = F1 = 1
Oh, dude, finding the nth term is like finding a needle in a haystack, but with numbers. So, if you look closely at this pattern, you'll notice that the difference between consecutive terms is increasing by 2 each time. It's like a math puzzle, but with less fun and more numbers. So, the nth term can be calculated by the formula n^2 + 4.
It is: nth term = 35-9n
The Nth triangular number is calculated by: N(N + 1) -------- 2 Hope this is useful!