Yes, 3 x 14 = 42. It is also divisible by these numbers: 1 2 3 6 7 21 and 42.
No. 42 is not evenly divisible by 12.
2 or 8
Numbers that are divisible by 2, 3, and 7 must be divisible by the least common multiple of these three numbers, which is 42. Therefore, any number that is a multiple of 42 will be divisible by 2, 3, and 7 simultaneously. Examples of such numbers include 42, 84, 126, 168, and so on.
First, let's find the multiples of 3 between 40 and 50. You can tell if any number is divisible by 3 by adding the digits and seeing if those are divisible by 3. (30 => 3+0 =3, thus 3 is divisible by 3. 31 => 3+1 =4, thus 31 is not.) We see that 40 and 41 are not divisible. What about 42? 4+2 = 6 which is divisible by 3, thus 42 is divisible by 3. Multiples of 3 must by 3 apart, so we can find the others by adding 3 to 42: 45, 48 Since the next number divisible by three is 51, we stop here. What about divisible by 4? Since 40/4 =10, we know 40 is divisible by 4. We can again add 4 to find the others: 44, 48. Thus we have the multiples of 3 between 40 and 50: 42, 45, 48 and the multiples of 4: 40, 44, 48. Since they have 48 in common, Sue must have been thinking of 48.
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
42 is divisible by 2, 3 and 6 but not by 9.
Yes. 126 divided by 3 is 42 42 is also divisible by 3. 42 ÷3 = 14 The prime factors of 126 are 2, 3, 3, and 7.
Yes, 3 x 14 = 42. It is also divisible by these numbers: 1 2 3 6 7 21 and 42.
42 is divisible by 2, 3 and 7
it is divisible by all three
42 is divisible by: 1 2 3 6 7 14 21 and 42.
42 is divisible by 2, 3, 6, & 7
No. 42 is not evenly divisible by 12.
2 or 8
Yes, both.
Out of that list, 2, 3 and 6