Nope - it's only divisible by 2. In order to be divisible by 5, it must end in either a 5 or zero. To be divisible by 10 it must end in a zero. For it to be divisible by 3, the total of the digits added together must divide by 3. The same rule applies for it to be divided by 9.
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.
No. A good test is to add up the digits of the number (5+3+2) and if that's divisible by three, then the original number is divisible by three.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.
It is evenly divisible by 2 and by 3.
Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;