5715 is not divisible by 2: the last digit is not an even number or 0
5715 is divisible by 3: as the last two digits when added together is a multiple of 3
5715 is divisible by 5: as the last digit is a 5 or 0
5715 is divisible by 9: as if u added all the digits of the number it will be divisible by 9, in this case 5 +7+1+5=18 and 18 is a multiple of 9
5715 is not divisible by 10: as the last digit is not a 0
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.
this # is divisible by 3, 5, and 9 :-) ;-P
The numbers that divide into 5715 are the factors of 5715. These are : 1, 3, 5, 9, 15, 45, 127, 381, 635, 1143, 1905 and 5715.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.
It is evenly divisible by 2 and by 3.