By 3 only.
It is not divisible by 2, 4, 5, 6, 9 & 10.
Division tests:
633 is odd (last digit is 3 which is not an even digit), so 633 is not divisible by 2.
(Can repeat the summing until a single digit remains; if this digit is 3, 6 or 9 (ie divisible by 3) then the original number is divisible by 3.)
6 + 6 + 3 = 15
1 + 5 = 6
6 is divisible by 3, so 663 is divisible by 3.
(Can repeat summing until a single digit remains; if this digit is 4 or 8 (ie divisible by 4) then the original number is divisible by 4.)
6 x 2 + 3 = 15
1 x 2 + 5 = 7
7 is not divisible by 4, so 663 is not divisible by 4.
Note: all multiples of 4 are even; 633 is odd so it cannot be divisible by 4 (the above test does not need to be done).
3 is not 0 nor 5, so 663 is not divisible by 5.
Fails 2 test (above), so 663 is not divisible by 6.
(Can repeat the summing until a single digit remains; if this digit is 9 (ie divisible by 9) then the original number is divisible by 9)
6 + 6 + 3 = 15
1 + 5 = 6
6 is not 9, so 663 is not divisible by 9.
3 is not 0, so 663 is not divisible by10.
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Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.