99
-1
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.
297 is divisible by (1 x 297) (99 x 3) (33 x 9) (27 x 11)
99 is divisible by 1, 3, 9, 11, 33, and 99.
99 is divisible by: 1, 3, 9, 11, 33, 99.
All multiples of 99 are divisible by 99
3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
102.
99
1, 3, 6, 9, 18, and some others :) * * * * * No, 99 is NOT divisible by 6 nor 18! The divisors are: 1, 3, 9, 11, 33 and 99
No 4 is divisible by 96 and 100. The answer would be 24 3/4
7.6154
99 is.
No, they are both divisible by 3.
99