102.
99 is divisible by 1, 3, 9, 11, 33, and 99.
3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
divisible by 2 means even number. so it can not be even number. divisible by 3 means add all the number and divide 3..number 99 is divisible by 3 we start 99+3=102 but it is even number..105,108,111,114,117,120. (108,114,120 are even number so they can not be answer) answers are 105, 111,117.
99 is.
99 is a composite number because it can be divisible by 1, 3, 9, 11, 33 and 99
99
-1
The divisible rule for 2 is if the last digit of the number is 0,2,4,6, or 8. The divisible rule for 3 is if the last 2 digits of the number is divisible by 3,03,06,09,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96, or 99.
A number divisible by 99 is any integer that can be expressed as (99n), where (n) is an integer. For example, 198 (which is (99 \times 2)) and 297 (which is (99 \times 3)) are both divisible by 99. The key characteristic of these numbers is that they must meet the divisibility rule for both 9 and 11, since 99 is the product of these two primes.
Definitely, 99/3 = 33
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
Correct, also applies to 9.yes, example: 99/3=33 9+9=18 18/3=6