102.
99 is divisible by 1, 3, 9, 11, 33, and 99.
3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
divisible by 2 means even number. so it can not be even number. divisible by 3 means add all the number and divide 3..number 99 is divisible by 3 we start 99+3=102 but it is even number..105,108,111,114,117,120. (108,114,120 are even number so they can not be answer) answers are 105, 111,117.
99 is.
99 is a composite number because it can be divisible by 1, 3, 9, 11, 33 and 99
-1
99
The divisible rule for 2 is if the last digit of the number is 0,2,4,6, or 8. The divisible rule for 3 is if the last 2 digits of the number is divisible by 3,03,06,09,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96, or 99.
Definitely, 99/3 = 33
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
Correct, also applies to 9.yes, example: 99/3=33 9+9=18 18/3=6
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.