Oh, what a happy little question! It looks like you have a special triangle there with side lengths 30, 32, and 34. Since the sum of the two shorter sides must be greater than the longest side for a triangle to exist, let's check if that's true here. If we add 30 and 32, we get 62, which is indeed greater than 34, so you can paint a beautiful triangle with those side lengths!
In any Pythagorean triple, the square of the two shortest sides is equal to the square of the longest side. For example, 32+42=52. Since it is impossible to have a right-angled triangle with a side of 1, it is impossible for two sides of a right-angled triangle to be of the same length.Therefore, a Pythagorean triple will always contain three differently-sized sides.
to find a perimeter of a triangle you need the add the lengths of the sides. So in this case, the sides are 18 + 32 + 252 so the answer would be 302meters Just a little hint : keep in mind what the measurements are in (i.e. centimeters, meters...) . you might to convert for some problems.
If it is a right triangle, then it's the famous 3,4,5 triangle often incorporated into test questions because no tables are needed for the sine and cosine trig functions. Note that 32+42 9+16 25 and the square root of 25 is 5. If it is not a right triangle and none ot the angles is given then the question is indeterminate.
Indeed they do, it is a Pythagorean Triple: 6*6 + 8*8 = 10*10. (62 + 82 = 102, 36 + 68 = 100, 100 = 100) The "basic" Pythagorean Triple of a 3, 4, 5 triangle works out like this: 32 + 42 = 52 9 + 16 = 25 25 = 25 Your triangle, the 6, 8, 10, figure, is a "doubling" of the cited "basic" triple, and any multiple of a Pythagorean Triple will also be another Pythagorean Triple, and a right triangle.
Yes because they comply with Pythagoras' theorem for a right angle triangle
Yes, the triangle is right-angled because 322 + 602 = 682. Given all three side lengths, you can use the Pythagorean relationship to determine whether a triangle is or is not right-angled. The right angle would be opposite the hypotenuse, 68.
The ratio of the three sides is 3:4:5. Now 32 + 42 = 9 + 16 = 25 = 52 So, by Pythagoras, the triangle must be right angled.
Oh, what a happy little question! It looks like you have a special triangle there with side lengths 30, 32, and 34. Since the sum of the two shorter sides must be greater than the longest side for a triangle to exist, let's check if that's true here. If we add 30 and 32, we get 62, which is indeed greater than 34, so you can paint a beautiful triangle with those side lengths!
5 because 32+42=52
Yes because the given dimensions comply with Pythagoras' theorem for a right angle triangle.
This is the simplest Pythagorean Triple (52 = 32 + 42) so it's a right(-angled) triangle
The two equal sides each measure 8 inches
Because the sum of the squares of the smaller sides equals the square of the largest side: 32+42 = 25 and 52 = 25
Yes.
how many lines of symmetry does a regular polygon with 32 sides have
A right triangle is triangle with an angle of 90 degrees. The sides a, b, and c of such a triangle satisfy the Pythagorean Theorem: a2 + b2 = c2 The largest side is normally referred to as "c" and is called the hypotenuse. The other two sides of sides, "a" and "b", and are called legs. For example, a common Pythagorean triplet, is of a right triangle with legs of length 3 and 4. The hypotenuse is of length 5. 32 + 42 = 52 9 + 16 = 25 25 = 25