Oh, what a happy little question! It looks like you have a special triangle there with side lengths 30, 32, and 34. Since the sum of the two shorter sides must be greater than the longest side for a triangle to exist, let's check if that's true here. If we add 30 and 32, we get 62, which is indeed greater than 34, so you can paint a beautiful triangle with those side lengths!
In any Pythagorean triple, the square of the two shortest sides is equal to the square of the longest side. For example, 32+42=52. Since it is impossible to have a right-angled triangle with a side of 1, it is impossible for two sides of a right-angled triangle to be of the same length.Therefore, a Pythagorean triple will always contain three differently-sized sides.
to find a perimeter of a triangle you need the add the lengths of the sides. So in this case, the sides are 18 + 32 + 252 so the answer would be 302meters Just a little hint : keep in mind what the measurements are in (i.e. centimeters, meters...) . you might to convert for some problems.
Indeed they do, it is a Pythagorean Triple: 6*6 + 8*8 = 10*10. (62 + 82 = 102, 36 + 68 = 100, 100 = 100) The "basic" Pythagorean Triple of a 3, 4, 5 triangle works out like this: 32 + 42 = 52 9 + 16 = 25 25 = 25 Your triangle, the 6, 8, 10, figure, is a "doubling" of the cited "basic" triple, and any multiple of a Pythagorean Triple will also be another Pythagorean Triple, and a right triangle.
To determine the length of the longest side of the triangle, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. In this case, the sum of the two short sides (3 and 4 inches) is 7 inches. Therefore, the longest side must be less than 7 inches in order for the triangle to be valid.
Yes because they comply with Pythagoras' theorem for a right angle triangle
Yes, the triangle is right-angled because 322 + 602 = 682. Given all three side lengths, you can use the Pythagorean relationship to determine whether a triangle is or is not right-angled. The right angle would be opposite the hypotenuse, 68.
The ratio of the three sides is 3:4:5. Now 32 + 42 = 9 + 16 = 25 = 52 So, by Pythagoras, the triangle must be right angled.
Oh, what a happy little question! It looks like you have a special triangle there with side lengths 30, 32, and 34. Since the sum of the two shorter sides must be greater than the longest side for a triangle to exist, let's check if that's true here. If we add 30 and 32, we get 62, which is indeed greater than 34, so you can paint a beautiful triangle with those side lengths!
5 because 32+42=52
Yes because the given dimensions comply with Pythagoras' theorem for a right angle triangle.
The triangle with sides measuring 3cm, 4cm, and 5cm is a right triangle. This can be determined by applying the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, 3^2 + 4^2 = 5^2, confirming that the triangle is a right triangle.
The two equal sides each measure 8 inches
Because the sum of the squares of the smaller sides equals the square of the largest side: 32+42 = 25 and 52 = 25
Yes.
how many lines of symmetry does a regular polygon with 32 sides have
A right triangle is triangle with an angle of 90 degrees. The sides a, b, and c of such a triangle satisfy the Pythagorean Theorem: a2 + b2 = c2 The largest side is normally referred to as "c" and is called the hypotenuse. The other two sides of sides, "a" and "b", and are called legs. For example, a common Pythagorean triplet, is of a right triangle with legs of length 3 and 4. The hypotenuse is of length 5. 32 + 42 = 52 9 + 16 = 25 25 = 25