CuO + 2HCl --> CuCl2 + H2O
This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
CuO + 2HCL - CuCl2 + H2O
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O
CuCl2 + H2S --> CuS + 2HCl Yes, this is the balanced equation here.
The HCl will react with the CuO in a double replacement reaction given by the equation: 2HCl + CuO --> CuCl2 + H2O. Copper(II) chloride is water soluble, so it will clean right out.
2HCl + Cu -> CuCl2 + H2 Assuming that it's Copper (II). CuCl2=Copper Chloride
CuSO4 + 2HCl -> CuCl2 + H2SO4 copper chloride and sulfuric acid
It is a double replacement reaction. MgCl2 + H2SO4 ---> MgSO4 + 2HCl
Cu(OH)2+2HCl=CuCl2+2H2O
We'll assume you mean Copper (II) Carbonate - CuCO3CuCO3 + 2 HCl --> CuCl2 + H2O + CO2It forms Copper (II) Chloride, carbon dioxide and water.
copper+hydrocloric acid=Copper chloride+hydrogen Cu+2HCl=CuCl2+H2 The first part of the salt is from the acid The second part is from the alkali, metal, or metal carbonate hydrochloric acid gives chloride sulfuric acid give sulfate nitric acid gives nitrate
No, Na2S(aq) + 2HCl(aq) ®2NaCl(aq) + H2S(g) is a double displacement reaction.
Hydrochloric acid CuCO3 + 2HCl --> CuCl2 + CO2 + H2O