CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
ATP plus H2O release energy (endergonic reaction) and P. Now, this P plus ADP becomes ATP (exergonic reaction). It's a cyclic process. It starts all over again at ATP plus H2O..
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
Na+ and Cl- are spectator ions.
2h2s + so2 - 2h20 + 3s
The balanced equation is: CuO + 2HCl → CuCl2 + H2O.
When copper(II) oxide (CuO) reacts with sulfuric acid (H2SO4), copper sulfate (CuSO4) and water (H2O) are produced. The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O.
cuo
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
To find the mass of hydrogen needed to react with 40g of copper oxide (CuO), first calculate the molar mass of CuO. Then, use stoichiometry to determine the moles of CuO present in 40g. From the balanced chemical equation CuO + H2 -> Cu + H2O, you can determine the mole ratio between CuO and H2. Finally, use the molar mass of hydrogen to calculate the mass of hydrogen needed to react.
The balanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) is: CuO + H2SO4 → CuSO4 + H2O
CuO + H2 ------> Cu + H2O. You shouldn't say "plus" for the reactions, it has to be the arrow as the arrow symbolises lots of complicated reactions, making it different to adding them together.
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
you obtain Cu from CuO only by reducing with hydrogen or carbon monooxide: CuO + H2 → Cu + H2O
The color of the precipitate formed when copper oxide (CuO) reacts with hydrochloric acid (HCl) is typically black or brown. This reaction produces copper chloride (CuCl2) along with water (H2O).
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O