k = x y x = k/y
K= 18.666666
I am assuming that k is the constant of proportionality so that f = k*a*t/b2 = 3*4*6/22 = 18
10-k=5
xy = K so K = 21
You need to have values for K, Br2 and 2KBr in order to find out the balance. For example, if you had the values as H2 + O2 = H20 the balanced chemical equation would be 10 H2 = H20.
Yes, the equation K + Br2 = KBr is a balanced chemical equation. For example, 2 K + Br2 = 2 KBr is one and another balance chemical equation is Fe + Cl2 = FeCl3.
The reaction 2KBr → 2K + Br2 is endothermic because heat must be supplied to break the bonds in potassium bromide (KBr) in order to form potassium (K) and bromine gas (Br2).
2KBr + 2H2O----->2KOH + Br2 + H2(g) this is the reaction in electrolysis of KBr in aqueous solution
2 K + Br2 -> 2 Kbr
To balance the equation K + Br₂ → KBr, you need to make sure the number of atoms of each element is the same on both sides of the equation. To balance this equation, you need to put a coefficient of 2 in front of KBr. This way, you will have 2 potassium atoms, 2 bromine atoms, and 2 KBr molecules on both sides of the equation.
cl2 kbr---kcl br2i think u mean balance it right ^^;here u have cl2 kbr---kcl br2 so what u do iscl2 kbr---kcl br2cl=2 cl=1k=1 k=1br=1 br=2so u need to balance that ...u need to add (2) to kbr and add (2) to kcl so that u have Cl2 (2)KBr ----(2)KCl Br2 hope that will help ^^ so now u have them balanced by adding 2 in front of kbr that means u r multiplying them by 2 so that K is going to be k=2 and br is going to be br=2 and u r doing that because there is br =1 on one side and the other side there is br=2 and u need them balanced. By adding 2 to kcl means that the other k now is k=2 so as cl. hope its helpful ^____~
The reaction of potassium bromide with chlorine is known as a displacement reaction, where the more reactive chlorine displaces the less reactive bromide to form potassium chloride and elemental bromine.
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
KBrO3 and KBr do not react with each other because they have same cation K+, but separately they react with H2SO4. 2KBrO3 + H2SO4 -------> K2SO4 + 2HBrO3 2KBr + H2SO4 ----------> K2SO4 + 2HBr
There are two atoms in one molecule KBr. One atom of potassium (K) and one atom of bromine (Br).
I believe it is already balanced. No coefficients neccessary