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When f varies jointly as a and t and inversely as the square of b what is the answer when determining f when k equals 3 a equals 4 t equals 6 and b equals 2?
Wiki User
∙ 2011-10-26 16:57:02
I am assuming that k is the constant of proportionality so that
f = k*a*t/b2 = 3*4*6/22 = 18
Wiki User
∙ 2011-10-26 16:57:02
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If y varies inversely as the square of x and y equals 4 when x equals 5 find y when x is 2?
25
If y varies inversely as the square of x and y equals 4 when x equals 5 findy y when x is 2?
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If y varies inversely as the square of x and y equals 4 when x equals 5 find y when x is 2?
25
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If y varies inversely as the square of x and y equals 4 when x equals 3 find y when x is 2?
The statement "y varies inversely as the square of x" means that in function form y(x) = k/x2, where k is an (initially) unknown constant. The second condition can be written in algebraic form as 4 = k/32 ; or k = 4 X 9 = 36; Then y(2) = 36/22 = 9.
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