Q: When f varies jointly as a and t and inversely as the square of b what is the answer when determining f when k equals 3 a equals 4 t equals 6 and b equals 2?

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25

y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25

Graham's law of effusion.

It is the square root of 10 times the square root of 10 equals 10

It is: the square root of 185 times the square root of 185 equals 185

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I'm pretty sure the answer is: C= de3k/ √m (C equals d times e cubed times k, divided by the square root of m).

25

C = k*a*d*e^3/sqrt(m) where k is a constant.

The gravity is proportional to both masses involved, and inversely proportional to the square of the distance.The gravity is proportional to both masses involved, and inversely proportional to the square of the distance.The gravity is proportional to both masses involved, and inversely proportional to the square of the distance.The gravity is proportional to both masses involved, and inversely proportional to the square of the distance.

No. The word is "inversely", not "conversely". And the force of gravity is inversely proportional to the square of the distance.

x2y = k (constant) so 36 x 2 ie 72 is the constant. If x = 3 then y = 72/9 = 8

The gravitational force between two objects decreases by a factor of 9 if the distance between the objects is tripled. This is because the gravitational force is inversely proportional to the square of the distance between the objects.

The statement "y varies inversely as the square of x" means that in function form y(x) = k/x2, where k is an (initially) unknown constant. The second condition can be written in algebraic form as 4 = k/32 ; or k = 4 X 9 = 36; Then y(2) = 36/22 = 9.

y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25

X=k/square of y

As x ∝ yz2 then x = kyz2 where k is a constant. Substituting the given figures, 40 = k*20*22 = 80k Then k = ½ and the formula is, x = ½yz2 So, x = ½ * 30 *32 = 135

5.