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What else can I help you with?
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
How do you make T the subject of this equation X is equal to W times A to the power of T?
X=W*(A)^T Use logarithms. T=log(A)/log(X/W)
Log x - log 6 equals log 15?
log(x) - log(6) = log(15)Add log(6) to each side:log(x) = log(15) + log(6) = log(15 times 6)x = 15 times 6x = 90
Log x plus log 2 equals log 2?
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
The log of a quotient is the log of the numerator divided by the log of the denominator?
Not quite. The log(x/y) = log(x) - log(y) In words, this reads "The log of a quotient is the difference of the log of the numerator and the log of the denominator."
What is log to the third power equal to?
Log (x^3) = 3 log(x) Log of x to the third power is three times log of x.
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
What does x equal when Ten to the power of x equals 4.6?
10x = 4.6 therefore log 10x = log 4.6 and that gives x = log 4.6
3 to the power of x equals 18 what does x equal?
3x = 18Take the logarithm of each side:x log(3) = log(18)Divide each side by log(3):x = log(18) / log(3) = 1.25527 / 0.47712x = 2.63093 (rounded)
How do you make T the subject of this equation X is equal to W times A to the power of T?
X=W*(A)^T Use logarithms. T=log(A)/log(X/W)
What does x equal in log 3 x equals 4?
log3(x)=4 x=3^4 x=81
What is the answer to log x6?
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)
What is the inverse of y equal the log of 2x?
y = log 2x → x = 1/2 <base of log>y So: y = log102x → x = 1/210y (common logs) y = loge2x → x = 1/2ey (natural logs)
An equation that has variables in both the numerator and denominator?
It has no specific name. For example f(x) = sin(x)/log(x) where x not equal to 1
Log base 3 of 81 plus log base 3 of 81?
Log base 3 of 81 is equal to 4, because 3 ^ 4 = 81. Therefore, two times log base 3 of 81 is equal to 2 x 4 = 8.
What is the log prosedure?
I assume you are asking how to solve a logarithmic equation. Well let's quickly review what the log function is: for the equation log(x)=y, we are saying that 10^y=x. So once you have isolated the logarithm, take the value of the base, raise it to the nth power (when 'n' is the value that the function is equal to) and set that equal to the value inside of the log.
Why can't you take the log of a negative number?
the log of a number, X, is equal to some value , N, and by definition 10 to the N power =X 10 to any power is always positive
