Perimeter = 81+81+29 = 191 units of measurement
eigthy one plus a number
The square root of 81 is: ±9 (9 or -9)A square root is a number which, when multiplied by itself, equals the original number. As 9 x 9 = 81 and -9 x -9 = 81, the answer is plus or minus nine.
The number that is being modified (8 in the following model) is referred to as the base number, or simply, base. Base Number----> 81 <------ Exponent
Without an equality sign and not knowing the plus or minus value of 81 it can't be solved. If you mean: z+81 = 9z-7 Then: z-9z = -7-81 => -8z = -88 By dividing both sides by -8: z = 11
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
1/2
It is 256.
log37 - log3x = 4 log3(7/x) = 4 7/x = 34 = 81 x = 7/81
No it is not. The log of any number, with the same number as the base, is always 1.
log9(x)=2 x=9^2 x=81
log3(x)=4 x=3^4 x=81
Adam-12 - 1968 Log 81 The Long Walk 1-14 was released on: USA: 4 January 1969
The above question rewritten as an equation:81/100=0.95d or to put all the numbers in similar terms:.81=.95dIn order to solve for d, remember the logarithm definition: logax=N means that aN=xTherefore,log.9(.81)=5dSince logs are base 10, you need to change to base .9, to solve the left side of the equation:log10(.81)/log10(.9)=2Therefore: 2=5d or d=2/5 or 0.4
78 + 79 + 80 + 80 + 81 + 81 = 479
I guess you mean the value of the power of 3 is at most 1000, not the value of 3^3, 3^4, ..., 3^1000 Logarithms tell you the power to which the base must be raised to get the number. eg for common logs (logs base 10) lg 100 = 2 since 10^2 = 100. To find the largest power of 3 which is at most 1000, the logs to base 3 or 1000 needs to be taken; if the result is not a whole number, the decimal portion is ignored (ie the number is truncated) and only the whole number is considered. [In the following log_3 means logs to base 3, and log is the log to any base, often common logs (lg) or natural logs (ln = logs to base e) are used (for the whole calculation).] log_3(1000) = log(1000)/log(3) ≈ 6.3 → highest power of 3 less than or equal to 1000 is 6, ie 3^6. Thus the powers of 3 in the range 3-1000 are: 3^1 = 3 3^2 = 9 3^3 = 27 3^4 = 81 3^5 = 243 3^6 = 729
81*82/2= 3321