4, 8, 12, 16
4
a common multiple. eg. 4 is a common multiple of 12 and 16.
A number that ends in 3 can't be a multiple of 4 because the 4 times table goes in a pattern, (e.g 4, 8, 12, 16, 20, 24.) If the number ends in either 0 2 4 6 8 then it couldbe a possible multiple of 4. It always ends in an even number. 3 is not an even number so it is not going to be the last number of a multiple of 4.
1, 2 and 4
Yes, 16 is a multiple of 4.
16 is a multiple of 4 because 4x4=16
16 is a multiple of 1 because 1 x 16 = 16 16 is a multiple of 4 because 4 x 4 = 16 16 is a multiple of 16 because 16 x 1 = 16 16 is the LCM of that set of three numbers because there is no smaller number that is a multiple of those three.
The least common multiple (lowest common multiple) is 16.It is 4 x 4 and 16 x 1.Where one number is a whole-number multiple of the other, it is the LCM.Since 16 is a multiple of 4, it is automatically the LCM.
Yes. It's also a multiple of 1, 2, 16, and 32.
16, 32, 48. Since 16 is divisible by 4. Every multiple of 16 is also a multiple of 4, so I just took the first 3 multiples of 16.
The least common multiple of 4 and 16 is 16It is: 16
16 is a multiple of 1 because 1 x 16 = 16 16 is a multiple of 4 because 4 x 4 = 16 16 is a multiple of 16 because 16 x 1 = 16 16 is the LCM of that set of three numbers because there is no smaller number that is a multiple of those three.
The least common multiple of 4, 8, and 16 is 16.
16:16.....4:4,8,12,16....So the LCM of 16 and 4 is 16. This is a very simple question. All you do is find the least common multiple of 16, and i stopped at 16 because i know that 4 is also going to have a 16. So then i found the least common multiple of 4.The only thing that was possible was to put 16.Since 16 is a multiple of 4, it is automatically the LCM.
Since 16 is a multiple of 4, it is automatically the LCM.
No, but vice versa holds true. Case and point: 6 is a multiple of 2, but not a multiple of 4. 8 is a multiple of 4, and is a multiple of 2. Because a factor of 4 is 2, every multiple of 4 is also a multiple of 2. But since 4 is not a factor of 2, rather, only half of it, only half of the multiples of 2 will be multiples of 4.