Yes, draw a 2 x 7 rectangle.
10 uints
It's impossible. The largest area for a rectangle with perimeter of 6 is 2.25, a perfect square with a length of 1.5 for each side. Any other combination yields a smaller area.
A rectangle with sides of 3 and 4 units will meet the requirements.
This browser is hopeless for drawing but consider the following two rectangles: a*b and (a+1)*(b-1). Their perimeter will be 2a+2b but unless a = b-1, their area will be different.
One side 8 long, other side 3 long.
Yes.
If we restrict ourselves to whole numbers, then 1 x 14 will have the least possible area.
10 uints
To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.
Yes. Make the length of each side 1/4 of the desired perimeter.
10 ------------------------------- | | 0.5 -------------------------------
0.000...1cm length on two sides. 19.999...9cm length on the other two.
9X2
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
You don't have to do anything at all. As soon as you draw a triangle, it automaticallyhas area. The only trick for you is to figure out how much area it has.
Draw it with dimensions of (6 cm) by (3 cm).
Squares are rectangles. Draw a 2 unit square.