No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5.
However, log10 5 = 1 - log102 = 2- log1020 .
or
log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4
But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
2 over 5 is an equivalent fraction for 20 over 50.
20/12 = 5/3
divide 20 by 5 = 4 divide 25 also by 5 = 5 4/5
4/5.
5 to 2
decimal equivalent to 5/20 = 0.25
It could be that: 5 to 20 is equivalent 1 to 4
5/20 = 0.25 <------------
No. 9/20 is 12.5% bigger than 2/5. 8/20 is equivalent to 2/5.
2logx-log5=-2 logx^2-log5=-2 log(x^2 / 5)=-2 x^2 / 5 = 10^-2 x^2=5(1/100) x^2=1/20 x=√(1/20)
5/20 = 1/4
5/20 = 1/4
5/20 = 1/4 in its simplest form
1/5 is equivalent to .20
20% = 0.2 or 1/5
log(5)125 = log(5) 5^(3) = 3log(5) 5 = 3 (1) = 3 Remember for any log base if the coefficient is the same as the base then the answer is '1' Hence log(10)10 = 1 log(a) a = 1 et.seq., You can convert the log base '5' , to log base '10' for ease of the calculator. Log(5)125 = log(10)125/log(10)5 Hence log(5)125 = log(10) 5^(3) / log(10)5 => log(5)125 = 3log(10)5 / log(10)5 Cancel down by 'log(10)5'. Hence log(5)125 = 3 NB one of the factors of 'log' is log(a) a^(n) The index number of 'n' can be moved to be a coefficient of the 'log'. Hence log(a) a^(n) = n*log(a)a Hope that helps!!!!!
20