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2logx-log5=-2
logx^2-log5=-2
log(x^2 / 5)=-2
x^2 / 5 = 10^-2
x^2=5(1/100)
x^2=1/20
x=√(1/20)
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∙ 11y ago
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Why is the answer for log x squared equals 2 different than 2log x equals 2?
log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)
How do you solve 2logx plus 3logx equals 10?
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
If 2 raised to the x equals 10 then what is x?
X is the log(to the base 2) of 10 = 3.324(rounded)
What is x if log x equals -3?
If the log of x equals -3 then x = 10-3 or 0.001or 1/1000.
What is the answer to x plus 5 equals 3?
x + 5 = 3 x = -2
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is x when 5 raised to the x-2 equals 70?
5x-2 = 70 ⇒ (x-2) log 5 = log 70 ⇒ x = log 70/log 5 + 2 ≈ 4.640 (You can use any base you like for the logs, as long as you use the same base for both of them.)
Why is the answer for log x squared equals 2 different than 2log x equals 2?
log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)
Log x plus log 2 equals log 2?
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
Does 5 equals log 5 to the x have an asymptote?
no
How do you solve 2logx plus 3logx equals 10?
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
How would you rewrite 7 to the power of x equals 5?
7x = 5x log(7) = log(5)x = log(5) / (log(7) = 0.82709 (rounded)
What s the G of x if it equals log 2 x plus 2?
G(x) = log(2x) + 2, obviously!
How do you solve log x plus 2 equals log 9?
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
What is 6255 to the power 2 5 to the power of?
6225^2=5^x 38,750,625=5^x log(38,750,625)=xlog(5) log(38,750,625)/log(5)=x x is approximately 10.856
Can anyone give an explanation and an answer to the following Find x -0.3 plus 5-5logd equals a plus 5-5log4d?
The explanation and answer to the following math equation to find x -0.3 plus 5-5 log (d) equals a plus 5-5 log 4 (d) is -5 log(d)+x+4.7 = a-5 log(4 d)+5. The solution is x = a-6.63147.
How do you solve for X in Log x plus 9 - Log x equals 2?
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