The square root of 4 is 2 (and -2) and is an integer.
Is the square root of a 100 is a integer
-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.
It is rational. The root of a perfect square, such as 4, is rational; the root of any positive integer that is not a perfect square is an irrational number.
Yes, the square root of 121 is 11
There is no formula relating to a perfect square but if you want a method 1. Find square root(x) 2. Take the integer component (integral value) of square root(x) 3 Add 1 to intenger(square root(x)) 4. square it So: (integer(square root(x)) + 1)^2
Yes, because the square root of 16 is 4 and as a whole number it is an integer
Yes.
Yes because the square root of 16 is 4
The square root of an integer is a CYCLOTOMIC integer.
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
The square root of 18, rounded to the nearest integer, is 4.
4.123105626 rounds down to 4
Yes, and it is 4
Yes. For example, the square root of 1 is 1, and the square root of 4 is 2.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
A number whose square root is an integer is called a "perfect square." Perfect squares are the squares of whole numbers, such as 0, 1, 4, 9, 16, and so on. For example, the square root of 16 is 4, which is an integer, making 16 a perfect square.
Is the square root of a 100 is a integer