No - the eight-bit binary code for 53 is 00110101 - if counting the binary number, when increasing the powers of two which you add together, you have written the indices at the top of the column in the wrong direction - it is the rightmost digit which starts at 20, increasing to 21, 22, 23, etc...
101011
101011
101011 in binary is 32+0+8+0+2+1=43
In binary code, each digit represents a power of 2, starting from the right with 2^0, then 2^1, 2^2, and so on. The binary number 101011 can be broken down as follows: 1*(2^5) + 0*(2^4) + 1*(2^3) + 0*(2^2) + 1*(2^1) + 1*(2^0). This simplifies to 32 + 0 + 8 + 0 + 2 + 1, which equals 43 in decimal form.
That IS the binary code.
101011
101011
101011 in binary is 32+0+8+0+2+1=43
43
In binary code, each digit represents a power of 2, starting from the right with 2^0, then 2^1, 2^2, and so on. The binary number 101011 can be broken down as follows: 1*(2^5) + 0*(2^4) + 1*(2^3) + 0*(2^2) + 1*(2^1) + 1*(2^0). This simplifies to 32 + 0 + 8 + 0 + 2 + 1, which equals 43 in decimal form.
0101 0011 (2) = 53 (16) which in BCD means 53
It is10101 011111 101011 101100 111111 101000 010111
Divide 54 by 2. Use the integer quotient obtained in this step as the dividend for the next step. Repeat the process until the quotient becomes 0. So we get answer 110110
32 + 8 + 2 + 1 = 1x25 + 0x24 + 1x23 + 0x22 + 1x21 + 1x20 = 101011 base 2
25 + 23 + 21 + 20 = 32 +8 +2+1 = 43
That IS the binary code.
00100001 is the binary code for 33