101011
101011
101011 in binary is 32+0+8+0+2+1=43
No - the eight-bit binary code for 53 is 00110101 - if counting the binary number, when increasing the powers of two which you add together, you have written the indices at the top of the column in the wrong direction - it is the rightmost digit which starts at 20, increasing to 21, 22, 23, etc...
8 = 10009 = 100110 = 101011 = 101112 = 110013 = 110114 = 111015 = 1111
101011
101011
101011 in binary is 32+0+8+0+2+1=43
43
No - the eight-bit binary code for 53 is 00110101 - if counting the binary number, when increasing the powers of two which you add together, you have written the indices at the top of the column in the wrong direction - it is the rightmost digit which starts at 20, increasing to 21, 22, 23, etc...
It is10101 011111 101011 101100 111111 101000 010111
8 = 10009 = 100110 = 101011 = 101112 = 110013 = 110114 = 111015 = 1111
That depends what you mean by "B", and what you mean by "binary code" assuming that by "binary code", you actually mean a binary representation of it's ascii value, then the answer is 1000010. The ascii value of the character "B" is 66 in decimal, which is 1000010 is that value in binary. If on the other hand, you mean "what is the binary value of the hexidecimal number B?", then the answer is 1011.
1111 in binary is 15 in decimal.
32 + 8 + 2 + 1 = 1x25 + 0x24 + 1x23 + 0x22 + 1x21 + 1x20 = 101011 base 2
Error: Malformed binary. Your binary code is must be divisible by 8.This looks like it is the beginning of a binary code, but is not computable into any text as is. Do you have the rest of the code?
25 + 23 + 21 + 20 = 32 +8 +2+1 = 43