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Q: Is the coordinate -2-4 a solution to the equation y3-2?
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Is -12 24 a solution to y equals x plus 12?

If (-12, 24) satisfies the equation (makes it a true statement), then it is a solution to the equation. Chek: y = x + 12; replace y with 24, and x with -12 24 =? -12 + 12 24 = 0 false Therefore, (-12, 24) is not a solution.


Is 21 a solution for x plus 3 equals 24 True or False?

21 is the only solution of that equation.


Is 7 a solution of the equation 24-y equals 17?

Yes, Y = 24-17 Y = 7


What is the solution of this equation -3b equals 24?

Divide both sides by -3: b = 24/(-3) = -8


Is 7x plus 2y equals 16 and -21x-6y equals 24 a no solution?

Multiplying the first equation by -3 gives -21x - 6y = -48 but the other equation gives 24 as the value of the same expression, so you are correct, there is no solution


Determine whether 28 is a solution of the equation x-11 is equal l3?

x-11=13, x-11+11 = 13+11, x=24 No, 28 is not the solution to the equation


29 plus d 54 24 25 26?

There is no solution to the equation 29 plus d 54 24 25 26.


Why is 24 not a factor of 12?

That simply means that there is no integer solution to:24n = 12 For comparison, 4 IS a factor; so the equation: 4n = 12 DOES have an integer solution.


What value of y would make the ordered pair a solution of the equation 4x and minus 2y 24 Given the ordered pair (3 y)?

Given the ordered pair (3, y), what value of ywould make the ordered pair a solution of the equation 4x − 2y = 24?12


Is 4 a solution of 6x equals 28-x?

6x = 28 - x (just replace x with 4) 6(4) =? 28 - 4 24 =? 28 - 4 24 = 24 True So that 4 is a solution of the given equation.


4x-y equals 33 x plus 5y equals 24 what is the solution of the system?

The solution of the system of the two equations, 4x - y = 33 and 5y = 24 may be found by first solving the second equation for y: y = 24/5. then substituting this value into the first equation to produce 4x - (24/5) = 33, or x = [33 + (24/5)]/4 = [(189/5)/4] = (189/20).


What two numbers add up to 2 and m ultiply to 24?

There are no such real numbers.Let the numbers be x and (2-x). The equation representing the question is:x(2-x) = 24 2x-x2 = 24 2x = x2+24 0 = x2-2x+24 x2-2x+24=0.In solving this equation, a=1, b=-2 and c=24. The discriminant is b2-4ac = (-2)2-4(1)(24) = 4-96 = -92.Since the discriminant is negative, the equation has no solution.