Yes!!! Except for '0' & '1'
0^(3) = 0
1^(3) = 1
However,
2^(3) = 8
yes
ONE
No. Here are some counterexamples:The cubic root of 0 is 0.The cubic root of 1 is 1.The cubic root of 1/8 is 1/2.The cubic root of -8 is -2.In general, the cubic root of a number will be less than the original number,Â?if your number is greater than 1.
No. They are the same.
Oh, dude, that's an easy one. A shape like a cube has more faces than vertices. Like, think about it, a cube has 6 faces but only 8 vertices. So, yeah, the faces totally outnumber the vertices in that situation.
The cube number greater than 50 but less than 100 is 64, which is (4^3) (4 cubed). The cube of 3 is 27, which is less than 50, and the cube of 5 is 125, which exceeds 100. Therefore, 64 is the only cube number that fits the criteria.
Yes, a prime number is always greater than 1.
It is 1/2 if it is a fair number cube which is rolled once.
It is 1/2.
A standard number cube, or die, has six faces numbered from 1 to 6. Since there are no numbers greater than 7 on a standard die, the probability of rolling a number greater than 7 is 0. Therefore, the probability is 0%.
The cube number that is greater than 50 but less than 100 is 64. This is because (4^3 = 64), and it falls within the specified range. The next cube, (5^3), equals 125, which exceeds 100.
The probability is zero. No number can be less than 3 and greater than 4.
88
no
Not always, if the smaller number is 0 or a negative number. Then their sum will be equal or less than the greater number.
50% or 3 out of 6.
NO