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In any division sum involving two numbers, such as 48/6 = 8, the first number, 48, is called the dividend. The second number is the divisor and the third, the answer, is called the quotient.
144,288
Dividing 96 in the ratio 48:1 gives the two parts as 48/49 and 1/49 of the total. So the first part is 48/49*96 and the second is 1/49*96, that is, 94.041 and 1.959
16, 32, 48, 64, 80
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.