No it is not. It is most likely to be geometric
t(n) = 3^(n-1) for n = 1, 2, 3, 4.
But it is equally possible that the sequence is generated by the following order 4 polynomial:
t(n) = (15*n^4 - 118*n^3 + 381*n^2 - 494*n - 240)/24 for n = 1, 2, 3, 4.
Or infinitely many other polynomials.
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U1 = 27 U{n+1} = U{n} - 3
what is the arthmetic sequence of 1 6 3 18 54 27 ? what is the missing terms ?
14
If you mean: 1 3 9 27 81 then it is 3*81 = 243
One of the simplest arithmetic arithmetic sequence is the counting numbers: 1, 2, 3, ... . The person who discovered that is prehistoric and, therefore, unknown.