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What is the 33rd term of this arithmetic sequence 12 7 2 -3 -8 and?
It is -148.
Descending arithmetic sequence?
An arithmetic sequence is where a constant is added to the base case, and then added again until the proscribed limit is reached. An example is 1, 3, 5, 7, where the constant is 2 and the base case is 1. The constant can be negative, such as -4, base case 16, which leads to a descending sequence of 16 12 8 4 0 -4 -8...
What is the sequence of 10 8 6 4?
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
What is the answer for finding the sum of the arithmetic sequence with a sigma notation with a 25 on top and t1 on the bottom then 5t-3 on the rightside?
To find the sum of 25 terms of these arithmetic sequence you can use the formula:Sn = (n/2)(a1 + an), where n is the number of terms in the sequence, a1 is the first term, and an is the last term of the sequence. In our case n = 25, so we need to compute a1 and a25.Since an = 5t - 3, thena1 = 5(1) - 3 = 5 - 3 = 2a25 = 5(25) - 3 = 125 - 3 = 122By substituting the values we know into the formula we have:S25 = (25/2)(2 + 122) = (25/2)(124) = 25 x 62 = 1,550Or you can use the formula:Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference.In order to find d, we need to find at least the value of 2 terms and subtract them.a1 = 2a2 = 5(2) - 3 = 10 - 3 = 7So d = 7 - 2 = 5By substituting the values we know into the formula we have:S25 = (25/2)[2(2) + (25 - 1)5]S25 = (25/2)(4+ 120) = (25/2)(124 = 25 x 62 = 1,550Thus, the sum of 25 terms of the given arithmetic sequence is 1,550.
What is a sum of a sequence?
If 1,2,3,4,5, is a sequence, then the sum is 1+2+3+4+5 = 15
