If the multiplicative inverse exists then, by definition, the product is 1 which is rational.
multiplicative inverse of a number 'p' = 1/p
The multiplicative inverse is also known as the reciprocal. The multiplicative inverse of a number "x" can be expressed as 1/x. In the case of a fraction, exchange numerator and denominator to get the multiplicative inverse.
The multiplicative inverse of a number is the reciprocal of that number. In this case, the multiplicative inverse of 16 is 1/16. This is because when you multiply a number by its multiplicative inverse, the result is always 1.
1/0.8 = 1.25
Sometimes. Also, when depends on what you mean by "opposite": the additive inverse or the multiplicative inverse.
Yes.
it means reciprocal, the number that multiplies by the original number to get a product of 1. The multiplicative inverse is always 1/x; x=5, then the multiplicative inverse is 1/5. If x=1/2 or .5, the multiplicative inverse is 1/.5, which is also 2.
multiplicative inverse of a number 'p' = 1/p
The multiplicative inverse is also known as the reciprocal. The multiplicative inverse of a number "x" can be expressed as 1/x. In the case of a fraction, exchange numerator and denominator to get the multiplicative inverse.
The multiplicative inverse of a number is the reciprocal of that number. In this case, the multiplicative inverse of 16 is 1/16. This is because when you multiply a number by its multiplicative inverse, the result is always 1.
The multiplicative inverse of a number ( x ) is defined as a number ( y ) such that ( x \times y = 1 ). Since zero multiplied by any number always equals zero, there is no number that can serve as a multiplicative inverse for zero. Therefore, the multiplicative inverse of zero is undefined.
Always, unless the original number is zero. This does not have an inverse.
To find the multiplicative inverse of a complex number z = (a + bi), divide its complex conjugate z* = (a - bi) by z* multiplied by z (and simplify): z = 4 + i z* = 4 - i multiplicative inverse of z: z* / (z*z) = (4 - i) / ((4 - i)(4 + i) = (4 - i) / (16 + 1) = (4- i) / 17 = 1/17 (4 - i)
1/0.8 = 1.25
Yes.
To solve for the multiplicative inverse of a number in Algebra 2, you simply take the reciprocal of that number. For a non-zero number ( a ), its multiplicative inverse is ( \frac{1}{a} ), since multiplying ( a ) by its inverse yields 1 (i.e., ( a \times \frac{1}{a} = 1 )). This concept is crucial when solving equations that involve fractions or when factoring expressions. Always remember that the multiplicative inverse is not defined for zero.
The product of two rational numbers is always a rational number.