Yes, but only if there is air, dust and other molecular scale debris attached to the ball. In a perfect universe, where nothing but the ball enters the water, then the volume would be exactly the same as that of the sphere.
It equals the mass of the object placed in it.
A beaker. Simply fill the beaker with a known quantity of liquid. Drop the object into the beaker, and measure the difference in the fluid levels.
the object volume is equal to the water displaced, or 10ml. Density is 15/10 = 1.5g/ml
They both weigh the same: 1kg = 1kg. The kg of butter has a greater volume and the kg of lead has a higher density.
no....its stil lthe same volume.(:
If you dropped the object into the beaker instead of submerging it, you would not be able to accurately measure the volume of the displaced water. The Archimedes' Principle method relies on the accurate measurement of the volume of water displaced by the object when it is fully submerged to determine its density. Dropping the object instead would introduce inaccuracies into the calculation.
Box A will displace more water if it has a greater volume compared to Box B, even though they have the same weight. The volume of water displaced is equal to the volume of the object immersed in it.
The density of the object is at least equal to, and possibly greater than, the density of the liquid in the beaker.
The buoyant force acting on an object submerged in water is equal to the weight of the water displaced by the object. The volume of water displaced is directly proportional to the buoyant force, meaning that the greater the volume of water displaced, the greater the buoyant force acting on the object.
A ruler no a better way is by dropping the cube in a liquid containg beaker displaced liquid will give you the volume
The easiest way is to place the object in a graduated beaker of water, and see how much the water rises when you put it in. Archimedes Principle says that the volume of the object is the same as the water displaced from the beaker.
Archimedes' principle states that the buoyant force acting on an object in a fluid is equal to the weight of the fluid displaced by the object. This means that the volume of the fluid displaced by the object directly influences the buoyant force experienced by the object; the greater the volume of fluid displaced, the greater the buoyant force acting on the object.
To measure the density of an object using a beaker, you would first fill the beaker with a known volume of liquid. Next, you would measure the initial volume of the liquid in the beaker and record it. Then, you would carefully lower the object into the beaker and measure the new volume of the liquid. The difference in volume of the liquid before and after adding the object divided by the mass of the object will give you the density.
stop cheating on gizmos, fool. :)The Answer: The mass of the water in the graduated cylinder is equal to the mass of the object.lol
Volume displacement is the method used to find the volume of small or irregularly shaped objects by noting the difference in the level of liquid before and after after immersing an object into a graduated cylinder or beaker of liquid. For a small object immersed in a graduated cylinder or beaker, the volume displaced by the object can be read directly from the scale on the container.
Buoyant force = volume x density x acceleration due to gravity So more the volume greater the buoyant force ___________________________________ The volume above must be volume of liquid displaced, not the volume of the object placed in the liquid.
The buoyant force acting on a body in water is directly proportional to the volume of water displaced by the body. This is known as Archimedes' principle. The greater the volume of water displaced, the greater the buoyant force exerted on the body.