It equals the mass of the object placed in it.
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The Easiest way- fil a marked measuring cup with enough water to cover the pear. Note the measurement. now push the pear into the water. Note the larger measurement. Subtract smaller from larger. Difference is the volume of water the pear displaced, which is equal to the volume of the pear.
You would measure the length width and heighth. Then you would multiply them all together. <><><> A better means would be to have a container that the rock will fit in, and fill it full of water. Place the rock in the container, which will overflow. Then remove the rock, and measure the volume of water you have to pour into the container to make it full again. The volume of the water will equal the volume that was displaced by the rock.
the object volume is equal to the water displaced, or 10ml. Density is 15/10 = 1.5g/ml
-- The aggregate density of the wood block is 700/1000 = 0.7 the density of water. -- So, as soon as the wood has displaced 0.7 of its volume in water, it has displaced its entire weight in water, and floats. -- The wood floats with 0.7 of its volume below the surface and 0.3 of its volume above it.
Yes, but only if there is air, dust and other molecular scale debris attached to the ball. In a perfect universe, where nothing but the ball enters the water, then the volume would be exactly the same as that of the sphere.