The Easiest way- fil a marked measuring cup with enough water to cover the pear. Note the measurement. now push the pear into the water. Note the larger measurement. Subtract smaller from larger. Difference is the volume of water the pear displaced, which is equal to the volume of the pear.
You would measure the length width and heighth. Then you would multiply them all together. <><><> A better means would be to have a container that the rock will fit in, and fill it full of water. Place the rock in the container, which will overflow. Then remove the rock, and measure the volume of water you have to pour into the container to make it full again. The volume of the water will equal the volume that was displaced by the rock.
the object volume is equal to the water displaced, or 10ml. Density is 15/10 = 1.5g/ml
-- The aggregate density of the wood block is 700/1000 = 0.7 the density of water. -- So, as soon as the wood has displaced 0.7 of its volume in water, it has displaced its entire weight in water, and floats. -- The wood floats with 0.7 of its volume below the surface and 0.3 of its volume above it.
Yes, but only if there is air, dust and other molecular scale debris attached to the ball. In a perfect universe, where nothing but the ball enters the water, then the volume would be exactly the same as that of the sphere.
The volume of water displaced is equal to the volume of the object submerged in water. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the water displaced by the object.
The water displaced by the body is equal to its volume.
the weight of the displaced water is equal to the weight of the object
The buoyant force acting on an object submerged in water is equal to the weight of the water displaced by the object. The volume of water displaced is directly proportional to the buoyant force, meaning that the greater the volume of water displaced, the greater the buoyant force acting on the object.
They are equal.
The buoyant force exerted by water on a submerged solid is equal to the weight of the water displaced by the solid. This means that the buoyant force increases with the volume of the solid submerged, as more water is displaced.
To calculate the volume of water displaced by an anchor on the ocean floor, you can use Archimedes' principle. The volume of water displaced will be equal to the volume of the anchor that is submerged underwater. By knowing the density of water and the weight of the anchor, you can calculate the volume of water displaced.
The volume of a fully submerged object is equal to the volume of water it displaces. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the water displaced by the object.
The volume of water displaced is equal to the volume of the object submerged into the water
By placing the object in water and the volume of water displaced is equal to the volume of the object immersed
The milliliters of a completely submerged object is equal to the milliliters of water displaced. This is in line with Archimedes' principle, which states that the volume of water displaced by an object is equal to the volume of the object submerged.
The volume of the water displaced by an object floating in a liquid is equal to the volume of the portion of the object that is submerged in the liquid. This is known as Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.