A polygon with n sides inscribed in a circle has an angle sum of 180xn-360
So the problem is find n so that 180n-360=9000 => n=48
The regular polygon with an angle sum of 9000 has 48 sides
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Yes, there is a polygon with an interior angle sum of 9000. The formula to find the sum of interior angles in a polygon is (n-2)*180 degrees, where n is the number of sides. To find the number of sides for a polygon with an interior angle sum of 9000, you would set the formula equal to 9000 and solve for n. So, (n-2)*180 = 9000, n-2 = 50, n = 52. Therefore, a polygon with 52 sides would have an interior angle sum of 9000 degrees.
180 x (52-2) = 9000 The sum of the interior angles is 9000 degrees.
9000
8999 rounded to the nearest ten is 9000.
They all round to 9000.