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Yes, there is a polygon with an interior angle sum of 9000. The formula to find the sum of interior angles in a polygon is (n-2)*180 degrees, where n is the number of sides. To find the number of sides for a polygon with an interior angle sum of 9000, you would set the formula equal to 9000 and solve for n. So, (n-2)*180 = 9000, n-2 = 50, n = 52. Therefore, a polygon with 52 sides would have an interior angle sum of 9000 degrees.
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Is there a regular polygon with an interior angle sum 9000?
A polygon with n sides inscribed in a circle has an angle sum of 180xn-360 So the problem is find n so that 180n-360=9000 => n=48 The regular polygon with an angle sum of 9000 has 48 sides
If the sum of the interior angle of a polygon equals 4320 degrees what is the measure of each interior angle of the polygon?
Im stuck on that too :/
What is the sum of the interior angle measures of a 25 - sided polygon?
The method of finding the sum of the interior angles of a polygon is by multiplying the (number of sides)-2 by 180, so the sum of the interior angle measures in a 25-sided polygon would be 23*180, or 4140 degrees.
What is the sum of a interior angle of a polygon with 38 sides?
Sum of interior angles of a 38 sided polygon: (38-2)*180 = 6480 degrees
What are the polygon angle rules?
The sum of the EXTERIOR angles of a polygon is 360 degrees. The sum of the INTERIOR angles of a polygon with n sides is (n-2)*180 degrees. If it is a regular polygon, each interior angle is (n-2)/n*180 degrees.
