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Is this domain (1 1) (2 2) (3 3) (3 6) (4 4) (5 5) (6 6) and this range 1 2 3 4 5 6 a function?
Whether or not is is a function depends on how the mapping is defined. If, for example the mapping is f(x, y) = x, where the coordinates of points in 2-d space are mapped to their abscissa or g(x, y) = y, where the coordinates of points in 2-d space are mapped to their ordinates then they are functions.
What else can I help you with?
What is the range when the domain is -2 1 3?
That depends on the specific function.
What is the example of the range and domain in a function?
A function is a mapping from one set to another. It may be many-to-one or one-to-one. The first of these sets is the domain and the second set is the range. Thus, for each value x in the domain, the function allocates the value f(x) which is a value in the range. For example, if the function is f(x) = x^2 and the domain is the integers in the interval [-2, 2], then the range is the set [0, 1, 4].
Domain and range of binary function?
x y -3 2 -1 6 1 -2 3 5
Domain is 2 range is 2 is this a function?
yes y=x Like 2=2
What is the domain and range of the sine function y is equal to 2 sin x?
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
How do you find the range of the function with the given domain?
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
What is the range of the function y equals x2 plus 1?
The answer depends on the domain. If the domain is the whole of the real numbers, the range in y ≥ 1. However, you can choose to have the domain as [1, 2] in which case the range will be [2, 5]. If you choose another domain you will get another range.
What is the range when the domain is -2 1 3?
That depends on the specific function.
What is the example of the range and domain in a function?
A function is a mapping from one set to another. It may be many-to-one or one-to-one. The first of these sets is the domain and the second set is the range. Thus, for each value x in the domain, the function allocates the value f(x) which is a value in the range. For example, if the function is f(x) = x^2 and the domain is the integers in the interval [-2, 2], then the range is the set [0, 1, 4].
Domain and range of binary function?
x y -3 2 -1 6 1 -2 3 5
What is the value for the RANGE when the DOMAIN is 2?
To determine the value of the RANGE when the DOMAIN is 2, we need a specific function or equation to evaluate. Without knowing the function associated with the DOMAIN of 2, we cannot provide a definitive RANGE value. Please provide the function or context for a more accurate answer.
What is the range of the function f(x) 4x plus 9 given the domain D -4 -2 0 2?
The range is {-7, 1, 9, 17}.
Domain is 2 range is 2 is this a function?
yes y=x Like 2=2
Is it ever possible for the domain and range to have different numbers of entries what happens when this is the case?
Yes. Typical example: y = x2. To avoid comparing infinite sets, restrict the function to integers between -3 and +3. Domain = -3, -2 , ... , 2 , 3. So |Domain| = 7 Range = 0, 1, 4, 9 so |Range| = 4 You have a function that is many-to-one. One consequence is that, without redefining its domain, the function cannot have an inverse.
What is the domain and range of the sine function y is equal to 2 sin x?
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
How do you find the domain and range of f ( x ) x 2 1?
To find the domain of the function ( f(x) = x^2 + 1 ), we identify the set of all possible input values for ( x ). Since this is a polynomial function, the domain is all real numbers, expressed as ( (-\infty, \infty) ). The range is determined by analyzing the output values; the minimum value of ( f(x) ) occurs at ( x = 0 ), giving ( f(0) = 1 ). Therefore, the range is ( [1, \infty) ).
Find domain and range of f x x 2 plus 1?
The function ( f(x) = x^2 + 1 ) is a quadratic function. The domain is all real numbers, expressed as ( (-\infty, \infty) ), since you can input any real number for ( x ). The range is ( [1, \infty) ) because the minimum value of the function occurs at ( x = 0 ), where ( f(0) = 1 ), and the function increases without bound as ( x ) moves away from zero.
