possible ways to get 7:
1+6=7
6+1=7
2+5=7
5+2=7
3+4=7
4+3=7
6 possible ways to get 7. There are 36 possible ways the two dice could be rolled, so you would get 6/36 or in this case, 35/210
Answer:35
If you roll a die 100 times, you would expect to get a 1 about 17 times, because the probability of getting a 1 is 1 in 6, or 0.1667. However, that is theoretical probability; experimental probability - the actual results of doing this 100 times - might not be 17, but if you did this a large number of times, the experimental results would indeed begin to approach the theoretical results.
The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads
It means there is a 5% chance of rain for the given day. If you were presented with 100 days of equivalent conditions, you would expect it to rain for 5 of them
The mean lets us know the approximate 'number per attempts'; it can help predict the number we expect for, say, a sports game or other statistics. It also enables us to predict the probability that something will have a particular value or will happen at a particular time.
I have to assume that you include 5 in your question then there are 6 sides and you can only win on 3 (1/3/5 ) or 3/6 which is 50% probability.
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If you roll a die 100 times, you would expect to get a 1 about 17 times, because the probability of getting a 1 is 1 in 6, or 0.1667. However, that is theoretical probability; experimental probability - the actual results of doing this 100 times - might not be 17, but if you did this a large number of times, the experimental results would indeed begin to approach the theoretical results.
The probability of drawing the Ace of Spades from a standard deck of 52 cards is 1 in 52, or about 0.01923. However, the number of times you can expect to draw it depends on random statistics. If you tested this a large number of times, shuffling the deck each time, you would expect about 1 out of every 52 trials to be the Ace of Spades, but that would only be in the long run, say for thousands and thousands of trials, and even then, it would not be exact. This is the difference between theoretical probability and experimental probability. Theoretical probability is based on pure statistics and the arrangement of the test. All you can say is that, for an infinite number of trials, you would expect 1 out of 52. In the case of experimental probability, you are limited by the number of trials that you can perform. Lets say you ran 10,000 trials. Theoretically, you would expect to draw the Ace of Spades about 192 times. In practice, you would have a range of results.
That means that you should roll a die many times, count how often you get the number "2", then divide this by the total number of rolls. If the die is "fair" (no extra weight on one side), you would expect this experimental probability to be somewhere close to the theoretical probability of 1/6, at least, if you roll often enough.
The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.
I'm going to assume you're looking for the probability of getting three heads out of three coin spins and that you're using a fair coin. For coin spins, theoretical probability is very simple. The probability of getting three heads in a row is 1/2 * 1/2 * 1/2 = 1/8. This means that if you tossed a coin three times, you'd expect to see three heads once every 8 trials. For experimental probability you need to define clear trials, for this experiment you can't just spin a coin over and over and count the number of times you see three heads in a row, for example, if you threw the following: H T H H T T H H H H H T T H T T T you have three cases where you have three heads in a row, but they all overlap so these are not independent trials and cannot be compared to the theoretical result. When conducting your experiment, you know that if you get a T in your trial, it doesn't matter what comes after, that trial has already failed to get three heads in a row. The trial is deemed a success if you get three heads in a row, naturally. As a result, if you threw the above sequence, you would to determine your experimental probability in the following way: H T fail H H T fail T fail H H H success H H T fail T fail H T fail T fail T fail In this example we have 8 trials and one success, therefore the experimental probability is 1/8. The sample variance (look it up), however is also 1/8, meaning that all you really know is that the experimental probability could be anywhere between 0 and 1/4. The only way to get the variance down (and therefore reduce your confidence interval) is to perform more and more trials. It's unlikely for the theoretical probability and experimental probability to be EXACTLY the same but the more trials you do, the more the experimental probability will converge on the theoretical probability.
I expect you mean the probability mass function (pmf). Please see the right sidebar in the linked page.
Pseudostratified Columnar
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.If a number cube (die) contains the numbers 1, 2, 3, 4, 5, and 6, and the cube is fair, then the probability of rolling a 6 is 1 in 6. If you roll the cube 10 times, you would expect to get 6's 10 / 6, or about 2 times. However, 10 trials is not a lot of trials, so the experimental outcome might not match the theoretical probability. In this case, the experimental probability matched the theoretical probability, but that is simply chance. If you repeat the experiment, so you will probably not get the same results.
The theoretical probability of HT or TH when two coins are tossed is 1/2 . (All possible outcomes are HH,TT,HT,TH). This means that when we run the experiment repeatedly we expect to get the desired result 1/2 of the time. Since you intend to toss the coins 40 times, 20 are expected.
To get the EXPERIMENTAL probability, you'll have to actually carry out the experiment. The EXPECTED probability is equal to a fraction; the numerator will be the number of pieces of papers that have the number 35, the denominator will be the total number of pieces. If you repeat the experiment often, you can expect the experimental probability to be close to the expected probability.
The probability of it snowing is an excellent question, usually answered with a statistic (incorrectly) by your local, friendly weatherman. Here's a quick guide to know when it will snow: IF: Your weatherman has said to expect several inches, expect a light dusting, possibly no-stick. IF: Your weatherman has said to expect nothing, prepare for a blizzard. IF: Your weatherman has said to expect sunshine, and clear skies, don't go on any parades, for fear of cliche. (Rain on parade)